Week 12 Calculus I Outline of Notes
by
(updated
I) Chapter 5: Finding Areas Under the Curve with curved sides
5.1 & 5.2: Using Riemann Sums on continuous f(x) on interval [a,b] with n subintervals
A = lim (n->∞) i=1∑n f(x) Δx = Δx [f(x1) + f(x2) + ... + f(xn)]
where A=Area, f(x)= height/length, Δx = (b-a)/n =base/width
p. 375, can sum rectangles where the estimate of A uses:
p. 370, Fig 4b, Rn=Right Endpoints coincide with curve (use xi), start @ a + Δx
p. 370, Fig 5, Ln=Left
Endpoints coincide with curve (use xi-1), start @ a = x0
p. 374, Fig 13, Sample Points (in middle somewhere) that coincide with curve (xi*)
p. 386, Fig 11, Mn=Midpoints coincide with curve (use ˜i), start @ (a+ (a+Δx))/2
where ˜i = (xi-1 + xi)/2 = midpoint of [xi-1, xi]
Note: The more rectangles, the better the approximation of A
5.2, p. 383, Properties of Summation (7-10)
p. 370, 5.1 Example 1 (using Right, Left, Mid)
II) 5.2 Definition of Definate Integral
a∫b f(x) dx = lim (n->∞) i=1∑n f(xi*) Δx
where ∫= "integral," a= "upper limit", b= "lower limit", f(x)= "integrand"
5.2, p. 391, #20
pp. 387-389, Properties of Definate Integral
5.2, p. 392, #48
III) 5.3 THE FUNDAMENTAL THEREOM OF CALCULUS (FTC)
Part 1 (FTC1)
if f continuous on [a,b] then
g(x) = a∫x f(t) dt
so g'(x) = lim (h->0) [g(x+h) - g(x)]/h = f(x),
f
is the derivative of g or g is the antiderivative of f
* make sure upper limit is x, if not change it using a substitution
5.3, p. 398, Example 4
Part 2 (FTC2)
if f continuous on [a,b] then
a∫b
f(x) dx = F(b)
- F(a) = F(x)]ab
where F is any antiderivative of f
5.3, p. 400, Example 6
* Beware of discontinuities on the interval and negative answers for Area
5.3, p. 401, Example 9